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easejs/test/Trait/ClassVirtualTest.js

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/**
* Tests overriding virtual class methods using mixins
*
* Copyright (C) 2014 Mike Gerwitz
*
* This file is part of GNU ease.js.
*
* ease.js is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program. If not, see <http://www.gnu.org/licenses/>.
*
* These tests vary from those in VirtualTest in that, rather than a class
* overriding a virtual method defined within a trait, a trait is overriding
* a method in the class that it is mixed into. In particular, since
* overrides require that the super method actually exist, this means that a
* trait must implement or extend a common interface.
*
* It is this very important (and powerful) system that allows traits to be
* used as stackable modifications, similar to how one would use the
* decorator pattern (but more tightly coupled).
*/
require( 'common' ).testCase(
{
caseSetUp: function()
{
this.Sut = this.require( 'Trait' );
this.Class = this.require( 'class' );
this.AbstractClass = this.require( 'class_abstract' );
this.Interface = this.require( 'interface' );
},
/**
* A trait may implement an interface I for a couple of reasons: to have
* the class mixed into be considered to of type I and to override
* methods. But, regardless of the reason, let's start with the
* fundamentals.
*/
'Traits may implement an interface': function()
{
var _self = this;
// simply make sure that the API is supported; nothing more.
this.assertDoesNotThrow( function()
{
_self.Sut.implement( _self.Interface( {} ) ).extend( {} );
} );
},
/**
* We would expect that the default behavior of implementing an
* interface I into a trait would create a trait with all abstract
* methods defined by I.
*/
'Traits implementing interfaces define abstract methods': function()
{
var I = this.Interface( { foo: [], bar: [] } ),
T = this.Sut.implement( I ).extend( {} );
var Class = this.Class,
AbstractClass = this.AbstractClass;
// T should contain both foo and bar as abstract methods, which we
// will test indirectly in the assertions below
// should fail because of abstract foo and bar
this.assertThrows( function()
{
Class.use( T ).extend( {} );
} );
// should succeed, since we can have abstract methods within an
// abstract class
this.assertDoesNotThrow( function()
{
AbstractClass.use( T ).extend( {} );
} );
// one remaining abstract method
this.assertDoesNotThrow( function()
{
AbstractClass.use( T ).extend( { foo: function() {} } );
} );
// both concrete
this.assertDoesNotThrow( function()
{
Class.use( T ).extend(
{
foo: function() {},
bar: function() {},
} );
} );
},
/**
* Just as classes implementing interfaces may choose to immediately
* provide concrete definitions for the methods declared in the
* interface (instead of becoming an abstract class), so too may traits.
*/
'Traits may provide concrete methods for interfaces': function()
{
var called = false;
var I = this.Interface( { foo: [] } ),
T = this.Sut.implement( I ).extend(
{
foo: function()
{
called = true;
},
} );
var Class = this.Class;
this.assertDoesNotThrow( function()
{
// should invoke concrete foo; class definition should not fail,
// because foo is no longer abstract
Class.use( T )().foo();
} );
this.assertOk( called );
},
/**
* Instances of class C mixing in some trait T implementing I will be
* considered to be of type I, since any method of I would either be
* defined within T, or would be implicitly abstract in T, requiring its
* definition within C; otherwise, C would have to be declared astract.
*/
'Instance of class mixing in trait implementing I is of type I':
function()
{
var I = this.Interface( {} ),
T = this.Sut.implement( I ).extend( {} );
this.assertOk(
this.Class.isA( I, this.Class.use( T )() )
);
},
/**
* The API for multiple interfaces should be the same for traits as it
* is for classes.
*/
'Trait can implement multiple interfaces': function()
{
var Ia = this.Interface( {} ),
Ib = this.Interface( {} ),
T = this.Sut.implement( Ia, Ib ).extend( {} ),
o = this.Class.use( T ).extend( {} )();
this.assertOk( this.Class.isA( Ia, o ) );
this.assertOk( this.Class.isA( Ib, o ) );
},
/**
* This is a concept borrowed from Scala: consider class C and trait T,
* both implementing interface I which declares method M. T should be
* able to override C.M so long as it is concrete, but to do so, we need
* some way of telling ease.js that we are overriding at time of mixin;
* otherwise, override does not make sense, because I.M is clearly
* abstract and there is nothing to override.
*/
'Trait can override virtual concrete interface methods at mixin':
function()
{
},
} );